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13114325224450 = 252262286504489
BaseRepresentation
bin1011111011010110101010…
…1100100100110000000010
31201102201100212120200011201
42332311222230210300002
53204331114224140300
643520345434531414
72522323130103562
oct276655254446002
951381325520151
1013114325224450
1141a6832776a6a
121579788b96b6a
137418a2296c18
14334a4581ada2
1517b20134766a
hexbed6ab24c02

13114325224450 has 12 divisors (see below), whose sum is σ = 24392644917570. Its totient is φ = 5245730089760.

The previous prime is 13114325224411. The next prime is 13114325224463. The reversal of 13114325224450 is 5442252341131.

It can be written as a sum of positive squares in 3 ways, for example, as 5038628706721 + 8075696517729 = 2244689^2 + 2841777^2 .

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 131143252195 + ... + 131143252294.

Almost surely, 213114325224450 is an apocalyptic number.

13114325224450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13114325224450 is a deficient number, since it is larger than the sum of its proper divisors (11278319693120).

13114325224450 is a wasteful number, since it uses less digits than its factorization.

13114325224450 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262286504501 (or 262286504496 counting only the distinct ones).

The product of its (nonzero) digits is 115200, while the sum is 37.

Adding to 13114325224450 its reverse (5442252341131), we get a palindrome (18556577565581).

The spelling of 13114325224450 in words is "thirteen trillion, one hundred fourteen billion, three hundred twenty-five million, two hundred twenty-four thousand, four hundred fifty".

Divisors: 1 2 5 10 25 50 262286504489 524573008978 1311432522445 2622865044890 6557162612225 13114325224450