Base | Representation |
---|---|
bin | 10011000101010111100… |
… | …000000010110111010100 |
3 | 11122101001000122020100110 |
4 | 103011113200002313110 |
5 | 132441303324342122 |
6 | 2442244121243020 |
7 | 163514350641432 |
oct | 23052740026724 |
9 | 4571030566313 |
10 | 1311433043412 |
11 | 4661a28449a8 |
12 | 1921b8333470 |
13 | 9688a96269b |
14 | 4768bb81d52 |
15 | 241a7a0390c |
hex | 13157802dd4 |
1311433043412 has 24 divisors (see below), whose sum is σ = 3060043089376. Its totient is φ = 437139682848.
The previous prime is 1311433043377. The next prime is 1311433043419. The reversal of 1311433043412 is 2143403341131.
It is a self number, because there is not a number n which added to its sum of digits gives 1311433043412.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311433043419) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 701418 + ... + 1764894.
Almost surely, 21311433043412 is an apocalyptic number.
1311433043412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1311433043412 is an abundant number, since it is smaller than the sum of its proper divisors (1748610045964).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311433043412 is a wasteful number, since it uses less digits than its factorization.
1311433043412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1166247 (or 1166245 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 1311433043412 its reverse (2143403341131), we get a palindrome (3454836384543).
The spelling of 1311433043412 in words is "one trillion, three hundred eleven billion, four hundred thirty-three million, forty-three thousand, four hundred twelve".
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