Base | Representation |
---|---|
bin | 1011111011010110101100… |
… | …1111001110111010011010 |
3 | 1201102201101111200021021010 |
4 | 2332311223033032322122 |
5 | 3204331124040410132 |
6 | 43520350401354350 |
7 | 2522323300244310 |
oct | 276655317167232 |
9 | 51381344607233 |
10 | 13114334310042 |
11 | 41a6837912119 |
12 | 15797900389b6 |
13 | 7418a4128504 |
14 | 334a46b040b0 |
15 | 17b20203e6cc |
hex | bed6b3cee9a |
13114334310042 has 128 divisors (see below), whose sum is σ = 30167477452800. Its totient is φ = 3723074663616.
The previous prime is 13114334310023. The next prime is 13114334310079. The reversal of 13114334310042 is 24001343341131.
It is a junction number, because it is equal to n+sod(n) for n = 13114334309991 and 13114334310009.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6979421259 + ... + 6979423137.
It is an arithmetic number, because the mean of its divisors is an integer number (235683417600).
Almost surely, 213114334310042 is an apocalyptic number.
13114334310042 is an abundant number, since it is smaller than the sum of its proper divisors (17053143142758).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13114334310042 is a wasteful number, since it uses less digits than its factorization.
13114334310042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3680.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 13114334310042 its reverse (24001343341131), we get a palindrome (37115677651173).
The spelling of 13114334310042 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty-four million, three hundred ten thousand, forty-two".
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