Base | Representation |
---|---|
bin | 10011000101010111100… |
… | …001110101000110101101 |
3 | 11122101001001112000020011 |
4 | 103011113201311012231 |
5 | 132441303434330331 |
6 | 2442244135253221 |
7 | 163514354630602 |
oct | 23052741650655 |
9 | 4571031460204 |
10 | 1311433511341 |
11 | 4661a3034518 |
12 | 1921b851a211 |
13 | 9688aa97675 |
14 | 4768bc646a9 |
15 | 241a7a973b1 |
hex | 131578751ad |
1311433511341 has 2 divisors, whose sum is σ = 1311433511342. Its totient is φ = 1311433511340.
The previous prime is 1311433511329. The next prime is 1311433511387. The reversal of 1311433511341 is 1431153341131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1311416619241 + 16892100 = 1145171^2 + 4110^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311433511341 - 211 = 1311433509293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311433511321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655716755670 + 655716755671.
It is an arithmetic number, because the mean of its divisors is an integer number (655716755671).
Almost surely, 21311433511341 is an apocalyptic number.
It is an amenable number.
1311433511341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311433511341 is an equidigital number, since it uses as much as digits as its factorization.
1311433511341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6480, while the sum is 31.
Adding to 1311433511341 its reverse (1431153341131), we get a palindrome (2742586852472).
The spelling of 1311433511341 in words is "one trillion, three hundred eleven billion, four hundred thirty-three million, five hundred eleven thousand, three hundred forty-one".
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