1311434130 has 64 divisors (see below), whose sum is σ = 3174432768. Its totient is φ = 346733760.

The previous prime is 1311434129. The next prime is 1311434147. The reversal of 1311434130 is 314341131.

It is a junction number, because it is equal to n+sod(n) for n = 1311434097 and 1311434106.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3423919 + ... + 3424301.

It is an arithmetic number, because the mean of its divisors is an integer number (49600512).

Almost surely, 2^1311434130 is an apocalyptic number.

1311434130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1311434130 is an abundant number, since it is smaller than the sum of its proper divisors (1862998638).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311434130 is a wasteful number, since it uses less digits than its factorization.

1311434130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1071.

The product of its (nonzero) digits is 432, while the sum is 21.

The square root of 1311434130 is about 36213.7284741574. The cubic root of 1311434130 is about 1094.5833238767.

Adding to 1311434130 its reverse (314341131), we get a palindrome (1625775261).

The spelling of 1311434130 in words is "one billion, three hundred eleven million, four hundred thirty-four thousand, one hundred thirty".