1311442401340 has 24 divisors (see below), whose sum is σ = 2754075223872. Its totient is φ = 524568164160.

The previous prime is 1311442401317. The next prime is 1311442401431. The reversal of 1311442401340 is 431042441131.

It is a junction number, because it is equal to n+sod(n) for n = 1311442401299 and 1311442401308.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 747405 + ... + 1783675.

It is an arithmetic number, because the mean of its divisors is an integer number (114753134328).

Almost surely, 2^{1311442401340} is an apocalyptic number.

1311442401340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1311442401340 is an abundant number, since it is smaller than the sum of its proper divisors (1442632822532).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311442401340 is a wasteful number, since it uses less digits than its factorization.

1311442401340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1099557 (or 1099555 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1311442401340 its reverse (431042441131), we get a palindrome (1742484842471).

The spelling of 1311442401340 in words is "one trillion, three hundred eleven billion, four hundred forty-two million, four hundred one thousand, three hundred forty".