1311443311333 has 2 divisors, whose sum is σ = 1311443311334. Its totient is φ = 1311443311332.

The previous prime is 1311443311327. The next prime is 1311443311351. The reversal of 1311443311333 is 3331133441131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1294447756644 + 16995554689 = 1137738^2 + 130367^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311443311333 - 2²⁹ = 1310906440421 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311443311295 and 1311443311304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311443311393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655721655666 + 655721655667.

It is an arithmetic number, because the mean of its divisors is an integer number (655721655667).

Almost surely, 2^{1311443311333} is an apocalyptic number.

It is an amenable number.

1311443311333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311443311333 is an equidigital number, since it uses as much as digits as its factorization.

1311443311333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11664, while the sum is 31.

Adding to 1311443311333 its reverse (3331133441131), we get a palindrome (4642576752464).

The spelling of 1311443311333 in words is "one trillion, three hundred eleven billion, four hundred forty-three million, three hundred eleven thousand, three hundred thirty-three".