Base | Representation |
---|---|
bin | 10011000101011010100… |
… | …111010111101000101111 |
3 | 11122101011122221220021001 |
4 | 103011122213113220233 |
5 | 132441410213421101 |
6 | 2442253225221131 |
7 | 163515554035033 |
oct | 23053247275057 |
9 | 4571148856231 |
10 | 1311485295151 |
11 | 46621a293459 |
12 | 1922119317a7 |
13 | 96898728985 |
14 | 47694aa41c3 |
15 | 241ac3c5901 |
hex | 1315a9d7a2f |
1311485295151 has 2 divisors, whose sum is σ = 1311485295152. Its totient is φ = 1311485295150.
The previous prime is 1311485295139. The next prime is 1311485295163. The reversal of 1311485295151 is 1515925841131.
It is a balanced prime because it is at equal distance from previous prime (1311485295139) and next prime (1311485295163).
It is a cyclic number.
It is not a de Polignac number, because 1311485295151 - 215 = 1311485262383 is a prime.
It is a super-2 number, since 2×13114852951512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311485295121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655742647575 + 655742647576.
It is an arithmetic number, because the mean of its divisors is an integer number (655742647576).
Almost surely, 21311485295151 is an apocalyptic number.
1311485295151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311485295151 is an equidigital number, since it uses as much as digits as its factorization.
1311485295151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 216000, while the sum is 46.
The spelling of 1311485295151 in words is "one trillion, three hundred eleven billion, four hundred eighty-five million, two hundred ninety-five thousand, one hundred fifty-one".
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