13115213231 has 2 divisors, whose sum is σ = 13115213232. Its totient is φ = 13115213230.

The previous prime is 13115213173. The next prime is 13115213233. The reversal of 13115213231 is 13231251131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13115213231 is a prime.

It is a super-2 number, since 2×13115213231² (a number of 21 digits) contains 22 as substring.

Together with 13115213233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13115213197 and 13115213206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13115213233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557606615 + 6557606616.

It is an arithmetic number, because the mean of its divisors is an integer number (6557606616).

Almost surely, 2^13115213231 is an apocalyptic number.

13115213231 is a deficient number, since it is larger than the sum of its proper divisors (1).

13115213231 is an equidigital number, since it uses as much as digits as its factorization.

13115213231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 540, while the sum is 23.

Adding to 13115213231 its reverse (13231251131), we get a palindrome (26346464362).

The spelling of 13115213231 in words is "thirteen billion, one hundred fifteen million, two hundred thirteen thousand, two hundred thirty-one".