Base | Representation |
---|---|
bin | 10011000101100011010… |
… | …001010010111000101111 |
3 | 11122101112210012020121222 |
4 | 103011203101102320233 |
5 | 132442204402102341 |
6 | 2442315453413555 |
7 | 163522266216641 |
oct | 23054321227057 |
9 | 4571483166558 |
10 | 1311630503471 |
11 | 466294252632 |
12 | 19225249a2bb |
13 | 968bc83a862 |
14 | 476aa0a2891 |
15 | 241ba00a44b |
hex | 13163452e2f |
1311630503471 has 2 divisors, whose sum is σ = 1311630503472. Its totient is φ = 1311630503470.
The previous prime is 1311630503423. The next prime is 1311630503539. The reversal of 1311630503471 is 1743050361131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311630503471 - 234 = 1294450634287 is a prime.
It is a super-3 number, since 3×13116305034713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311630503371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655815251735 + 655815251736.
It is an arithmetic number, because the mean of its divisors is an integer number (655815251736).
Almost surely, 21311630503471 is an apocalyptic number.
1311630503471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311630503471 is an equidigital number, since it uses as much as digits as its factorization.
1311630503471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 35.
The spelling of 1311630503471 in words is "one trillion, three hundred eleven billion, six hundred thirty million, five hundred three thousand, four hundred seventy-one".
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