Base | Representation |
---|---|
bin | 10011000101100011010… |
… | …001010010110111111111 |
3 | 11122101112210012020120012 |
4 | 103011203101102313333 |
5 | 132442204402102143 |
6 | 2442315453413435 |
7 | 163522266216542 |
oct | 23054321226777 |
9 | 4571483166505 |
10 | 1311630503423 |
11 | 466294252599 |
12 | 19225249a27b |
13 | 968bc83a826 |
14 | 476aa0a2859 |
15 | 241ba00a418 |
hex | 13163452dff |
1311630503423 has 2 divisors, whose sum is σ = 1311630503424. Its totient is φ = 1311630503422.
The previous prime is 1311630503387. The next prime is 1311630503471. The reversal of 1311630503423 is 3243050361131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311630503423 - 220 = 1311629454847 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1311630503423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311630508423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655815251711 + 655815251712.
It is an arithmetic number, because the mean of its divisors is an integer number (655815251712).
Almost surely, 21311630503423 is an apocalyptic number.
1311630503423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311630503423 is an equidigital number, since it uses as much as digits as its factorization.
1311630503423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 32.
Adding to 1311630503423 its reverse (3243050361131), we get a palindrome (4554680864554).
The spelling of 1311630503423 in words is "one trillion, three hundred eleven billion, six hundred thirty million, five hundred three thousand, four hundred twenty-three".
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