1311645262001 has 2 divisors, whose sum is σ = 1311645262002. Its totient is φ = 1311645262000.

The previous prime is 1311645261977. The next prime is 1311645262003. The reversal of 1311645262001 is 1002625461131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1275182977600 + 36462284401 = 1129240^2 + 190951^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311645262001 is a prime.

Together with 1311645262003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1311645262003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655822631000 + 655822631001.

It is an arithmetic number, because the mean of its divisors is an integer number (655822631001).

Almost surely, 2^{1311645262001} is an apocalyptic number.

It is an amenable number.

1311645262001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311645262001 is an equidigital number, since it uses as much as digits as its factorization.

1311645262001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 32.

The spelling of 1311645262001 in words is "one trillion, three hundred eleven billion, six hundred forty-five million, two hundred sixty-two thousand, one".