131181019241 has 2 divisors, whose sum is σ = 131181019242. Its totient is φ = 131181019240.

The previous prime is 131181019223. The next prime is 131181019243. The reversal of 131181019241 is 142910181131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100615840000 + 30565179241 = 317200^2 + 174829^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131181019241 is a prime.

It is a super-2 number, since 2×131181019241² (a number of 23 digits) contains 22 as substring.

Together with 131181019243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131181019198 and 131181019207.

It is not a weakly prime, because it can be changed into another prime (131181019243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65590509620 + 65590509621.

It is an arithmetic number, because the mean of its divisors is an integer number (65590509621).

Almost surely, 2^131181019241 is an apocalyptic number.

It is an amenable number.

131181019241 is a deficient number, since it is larger than the sum of its proper divisors (1).

131181019241 is an equidigital number, since it uses as much as digits as its factorization.

131181019241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 32.

The spelling of 131181019241 in words is "one hundred thirty-one billion, one hundred eighty-one million, nineteen thousand, two hundred forty-one".