Base | Representation |
---|---|
bin | 11000011011111000… |
… | …11110100110000010 |
3 | 1020212021110010020202 |
4 | 30031330132212002 |
5 | 203331412002100 |
6 | 10005434405202 |
7 | 643045316141 |
oct | 141574364602 |
9 | 36767403222 |
10 | 13118859650 |
11 | 5622288476 |
12 | 2661590802 |
13 | 1310bb9860 |
14 | 8c6469758 |
15 | 51bace7d5 |
hex | 30df1e982 |
13118859650 has 48 divisors (see below), whose sum is σ = 26594797824. Its totient is φ = 4785506880.
The previous prime is 13118859647. The next prime is 13118859671. The reversal of 13118859650 is 5695881131.
13118859650 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13118859595 and 13118859604.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 67634 + ... + 175533.
It is an arithmetic number, because the mean of its divisors is an integer number (554058288).
Almost surely, 213118859650 is an apocalyptic number.
13118859650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13118859650 is an abundant number, since it is smaller than the sum of its proper divisors (13475938174).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13118859650 is a wasteful number, since it uses less digits than its factorization.
13118859650 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 243275 (or 243270 counting only the distinct ones).
The product of its (nonzero) digits is 259200, while the sum is 47.
The spelling of 13118859650 in words is "thirteen billion, one hundred eighteen million, eight hundred fifty-nine thousand, six hundred fifty".
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