Base | Representation |
---|---|
bin | 1011111011101000110010… |
… | …1000011101011010001111 |
3 | 1201110011220212122102112101 |
4 | 2332322030220131122033 |
5 | 3204421100010212242 |
6 | 43522512242015531 |
7 | 2522554514066206 |
oct | 276721450353217 |
9 | 51404825572471 |
10 | 13119189538447 |
11 | 41a88a9529083 |
12 | 157a7060475a7 |
13 | 742198c98c25 |
14 | 334d8787c23d |
15 | 17b3d83ea9b7 |
hex | bee8ca1d68f |
13119189538447 has 2 divisors, whose sum is σ = 13119189538448. Its totient is φ = 13119189538446.
The previous prime is 13119189538331. The next prime is 13119189538457. The reversal of 13119189538447 is 74483598191131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13119189538447 - 215 = 13119189505679 is a prime.
It is a super-2 number, since 2×131191895384472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13119189538457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6559594769223 + 6559594769224.
It is an arithmetic number, because the mean of its divisors is an integer number (6559594769224).
Almost surely, 213119189538447 is an apocalyptic number.
13119189538447 is a deficient number, since it is larger than the sum of its proper divisors (1).
13119189538447 is an equidigital number, since it uses as much as digits as its factorization.
13119189538447 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 26127360, while the sum is 64.
The spelling of 13119189538447 in words is "thirteen trillion, one hundred nineteen billion, one hundred eighty-nine million, five hundred thirty-eight thousand, four hundred forty-seven".
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