13120114133020 has 24 divisors (see below), whose sum is σ = 27552590448768. Its totient is φ = 5247978840000.

The previous prime is 13120114133011. The next prime is 13120114133069. The reversal of 13120114133020 is 2033141102131.

It is a super-2 number, since 2×13120114133020² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13120114132982 and 13120114133000.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2550156 + ... + 5722195.

It is an arithmetic number, because the mean of its divisors is an integer number (1148024602032).

Almost surely, 2^{13120114133020} is an apocalyptic number.

13120114133020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13120114133020 is an abundant number, since it is smaller than the sum of its proper divisors (14432476315748).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13120114133020 is a wasteful number, since it uses less digits than its factorization.

13120114133020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8351661 (or 8351659 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13120114133020 its reverse (2033141102131), we get a palindrome (15153255235151).

The spelling of 13120114133020 in words is "thirteen trillion, one hundred twenty billion, one hundred fourteen million, one hundred thirty-three thousand, twenty".