Base | Representation |
---|---|
bin | 1011111011101100001110… |
… | …1111110011100101000111 |
3 | 1201110021022022120200000021 |
4 | 2332323003233303211013 |
5 | 3204424443214224033 |
6 | 43523144113000011 |
7 | 2522616442505032 |
oct | 276730357634507 |
9 | 51407268520007 |
10 | 13120114211143 |
11 | 41a9233482395 |
12 | 157a923853007 |
13 | 7422b5720834 |
14 | 3350345bc019 |
15 | 17b43e69cb2d |
hex | beec3bf3947 |
13120114211143 has 2 divisors, whose sum is σ = 13120114211144. Its totient is φ = 13120114211142.
The previous prime is 13120114211051. The next prime is 13120114211249. The reversal of 13120114211143 is 34111241102131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13120114211143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13120114221143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560057105571 + 6560057105572.
It is an arithmetic number, because the mean of its divisors is an integer number (6560057105572).
Almost surely, 213120114211143 is an apocalyptic number.
13120114211143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120114211143 is an equidigital number, since it uses as much as digits as its factorization.
13120114211143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 13120114211143 its reverse (34111241102131), we get a palindrome (47231355313274).
The spelling of 13120114211143 in words is "thirteen trillion, one hundred twenty billion, one hundred fourteen million, two hundred eleven thousand, one hundred forty-three".
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