13120122401 has 2 divisors, whose sum is σ = 13120122402. Its totient is φ = 13120122400.

The previous prime is 13120122391. The next prime is 13120122403. The reversal of 13120122401 is 10422102131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9888313600 + 3231808801 = 99440^2 + 56849^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13120122401 is a prime.

It is a super-3 number, since 3×13120122401³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

Together with 13120122403, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13120122401.

It is not a weakly prime, because it can be changed into another prime (13120122403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560061200 + 6560061201.

It is an arithmetic number, because the mean of its divisors is an integer number (6560061201).

Almost surely, 2^13120122401 is an apocalyptic number.

It is an amenable number.

13120122401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13120122401 is an equidigital number, since it uses as much as digits as its factorization.

13120122401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 13120122401 its reverse (10422102131), we get a palindrome (23542224532).

The spelling of 13120122401 in words is "thirteen billion, one hundred twenty million, one hundred twenty-two thousand, four hundred one".