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13120130320040 = 235536188740717
BaseRepresentation
bin1011111011101100010010…
…1101010000011010101000
31201110021100102220002021002
42332323010231100122220
53204430011330220130
643523145450134132
72522620026436532
oct276730455203250
951407312802232
1013120130320040
1141a9241585227
12157a929121348
137422b8b70b23
143350367b2852
1517b440cd0b45
hexbeec4b506a8

13120130320040 has 32 divisors (see below), whose sum is σ = 30077279889480. Its totient is φ = 5149032275712.

The previous prime is 13120130320007. The next prime is 13120130320217. The reversal of 13120130320040 is 4002303102131.

13120130320040 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 8301394113796 + 4818736206244 = 2881214^2 + 2195162^2 .

It is a super-2 number, since 2×131201303200402 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13120130319994 and 13120130320021.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3094368239 + ... + 3094372478.

Almost surely, 213120130320040 is an apocalyptic number.

13120130320040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13120130320040 is an abundant number, since it is smaller than the sum of its proper divisors (16957149569440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13120130320040 is a wasteful number, since it uses less digits than its factorization.

13120130320040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6188740781 (or 6188740777 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13120130320040 its reverse (4002303102131), we get a palindrome (17122433422171).

The spelling of 13120130320040 in words is "thirteen trillion, one hundred twenty billion, one hundred thirty million, three hundred twenty thousand, forty".

Divisors: 1 2 4 5 8 10 20 40 53 106 212 265 424 530 1060 2120 6188740717 12377481434 24754962868 30943703585 49509925736 61887407170 123774814340 247549628680 328003258001 656006516002 1312013032004 1640016290005 2624026064008 3280032580010 6560065160020 13120130320040