Base | Representation |
---|---|
bin | 1011111011101100010101… |
… | …1110011110001001001111 |
3 | 1201110021101100011112111112 |
4 | 2332323011132132021033 |
5 | 3204430023131040302 |
6 | 43523151030442235 |
7 | 2522620244211602 |
oct | 276730536361117 |
9 | 51407340145445 |
10 | 13120143221327 |
11 | 41a924889714a |
12 | 157a93150337b |
13 | 7422bb73a11c |
14 | 3350383b0339 |
15 | 17b441ecd552 |
hex | beec579e24f |
13120143221327 has 2 divisors, whose sum is σ = 13120143221328. Its totient is φ = 13120143221326.
The previous prime is 13120143221287. The next prime is 13120143221429. The reversal of 13120143221327 is 72312234102131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13120143221327 - 28 = 13120143221071 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13120143221293 and 13120143221302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13120143221027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560071610663 + 6560071610664.
It is an arithmetic number, because the mean of its divisors is an integer number (6560071610664).
Almost surely, 213120143221327 is an apocalyptic number.
13120143221327 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120143221327 is an equidigital number, since it uses as much as digits as its factorization.
13120143221327 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 13120143221327 its reverse (72312234102131), we get a palindrome (85432377323458).
The spelling of 13120143221327 in words is "thirteen trillion, one hundred twenty billion, one hundred forty-three million, two hundred twenty-one thousand, three hundred twenty-seven".
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