Base | Representation |
---|---|
bin | 11101110101001110110111… |
… | …011101101011111001011111 |
3 | 122012112201212012212101001112 |
4 | 131311032313131223321133 |
5 | 114144101024131102143 |
6 | 1143013040012332235 |
7 | 36430664043221153 |
oct | 3565166735537137 |
9 | 565481765771045 |
10 | 131201444003423 |
11 | 388942467a8482 |
12 | 1286b87617407b |
13 | 5829321087491 |
14 | 24582803b1063 |
15 | 1027cb5e1be18 |
hex | 7753b776be5f |
131201444003423 has 2 divisors, whose sum is σ = 131201444003424. Its totient is φ = 131201444003422.
The previous prime is 131201444003419. The next prime is 131201444003429. The reversal of 131201444003423 is 324300444102131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131201444003423 - 22 = 131201444003419 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131201444003423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131201444003429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600722001711 + 65600722001712.
It is an arithmetic number, because the mean of its divisors is an integer number (65600722001712).
Almost surely, 2131201444003423 is an apocalyptic number.
131201444003423 is a deficient number, since it is larger than the sum of its proper divisors (1).
131201444003423 is an equidigital number, since it uses as much as digits as its factorization.
131201444003423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 131201444003423 its reverse (324300444102131), we get a palindrome (455501888105554).
The spelling of 131201444003423 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred forty-four million, three thousand, four hundred twenty-three".
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