Base | Representation |
---|---|
bin | 11101110101001111011011… |
… | …110100110110000101111111 |
3 | 122012112210102201210011111101 |
4 | 131311033123310312011333 |
5 | 114144103301314214041 |
6 | 1143013220324033531 |
7 | 36431015131451104 |
oct | 3565173364660577 |
9 | 565483381704441 |
10 | 131202054054271 |
11 | 3889452a0a0732 |
12 | 1286ba065328a7 |
13 | 58293ba591b05 |
14 | 24582db412aab |
15 | 1027cee772b31 |
hex | 7753dbd3617f |
131202054054271 has 2 divisors, whose sum is σ = 131202054054272. Its totient is φ = 131202054054270.
The previous prime is 131202054054259. The next prime is 131202054054341. The reversal of 131202054054271 is 172450450202131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131202054054271 - 243 = 122405961032063 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131202054054271.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131202054054371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601027027135 + 65601027027136.
It is an arithmetic number, because the mean of its divisors is an integer number (65601027027136).
Almost surely, 2131202054054271 is an apocalyptic number.
131202054054271 is a deficient number, since it is larger than the sum of its proper divisors (1).
131202054054271 is an equidigital number, since it uses as much as digits as its factorization.
131202054054271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67200, while the sum is 37.
The spelling of 131202054054271 in words is "one hundred thirty-one trillion, two hundred two billion, fifty-four million, fifty-four thousand, two hundred seventy-one".
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