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131202054054341 is a prime number
BaseRepresentation
bin11101110101001111011011…
…110100110110000111000101
3122012112210102201210011120222
4131311033123310312013011
5114144103301314214331
61143013220324034125
736431015131451234
oct3565173364660705
9565483381704528
10131202054054341
113889452a0a0796
121286ba06532945
1358293ba591b5a
1424582db412b1b
151027cee772b7b
hex7753dbd361c5

131202054054341 has 2 divisors, whose sum is σ = 131202054054342. Its totient is φ = 131202054054340.

The previous prime is 131202054054271. The next prime is 131202054054349. The reversal of 131202054054341 is 143450450202131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126928862245441 + 4273191808900 = 11266271^2 + 2067170^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131202054054341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131202054054349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601027027170 + 65601027027171.

It is an arithmetic number, because the mean of its divisors is an integer number (65601027027171).

Almost surely, 2131202054054341 is an apocalyptic number.

It is an amenable number.

131202054054341 is a deficient number, since it is larger than the sum of its proper divisors (1).

131202054054341 is an equidigital number, since it uses as much as digits as its factorization.

131202054054341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 57600, while the sum is 35.

The spelling of 131202054054341 in words is "one hundred thirty-one trillion, two hundred two billion, fifty-four million, fifty-four thousand, three hundred forty-one".