Base | Representation |
---|---|
bin | 11101110101001111011011… |
… | …110100110110000111000101 |
3 | 122012112210102201210011120222 |
4 | 131311033123310312013011 |
5 | 114144103301314214331 |
6 | 1143013220324034125 |
7 | 36431015131451234 |
oct | 3565173364660705 |
9 | 565483381704528 |
10 | 131202054054341 |
11 | 3889452a0a0796 |
12 | 1286ba06532945 |
13 | 58293ba591b5a |
14 | 24582db412b1b |
15 | 1027cee772b7b |
hex | 7753dbd361c5 |
131202054054341 has 2 divisors, whose sum is σ = 131202054054342. Its totient is φ = 131202054054340.
The previous prime is 131202054054271. The next prime is 131202054054349. The reversal of 131202054054341 is 143450450202131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 126928862245441 + 4273191808900 = 11266271^2 + 2067170^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131202054054341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131202054054349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601027027170 + 65601027027171.
It is an arithmetic number, because the mean of its divisors is an integer number (65601027027171).
Almost surely, 2131202054054341 is an apocalyptic number.
It is an amenable number.
131202054054341 is a deficient number, since it is larger than the sum of its proper divisors (1).
131202054054341 is an equidigital number, since it uses as much as digits as its factorization.
131202054054341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 35.
The spelling of 131202054054341 in words is "one hundred thirty-one trillion, two hundred two billion, fifty-four million, fifty-four thousand, three hundred forty-one".
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