Base | Representation |
---|---|
bin | 10011000101111010100… |
… | …100011100111011011011 |
3 | 11122102120000201220122121 |
4 | 103011322210130323123 |
5 | 132444004434320212 |
6 | 2442422340002111 |
7 | 163535053621531 |
oct | 23057244347333 |
9 | 4572500656577 |
10 | 1312021401307 |
11 | 4664749709a1 |
12 | 192341390337 |
13 | 96952813156 |
14 | 47705d78151 |
15 | 241de4c1d07 |
hex | 1317a91cedb |
1312021401307 has 2 divisors, whose sum is σ = 1312021401308. Its totient is φ = 1312021401306.
The previous prime is 1312021401289. The next prime is 1312021401349. The reversal of 1312021401307 is 7031041202131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312021401307 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312021401707) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656010700653 + 656010700654.
It is an arithmetic number, because the mean of its divisors is an integer number (656010700654).
Almost surely, 21312021401307 is an apocalyptic number.
1312021401307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312021401307 is an equidigital number, since it uses as much as digits as its factorization.
1312021401307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 1312021401307 its reverse (7031041202131), we get a palindrome (8343062603438).
The spelling of 1312021401307 in words is "one trillion, three hundred twelve billion, twenty-one million, four hundred one thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •