1312021401349 has 2 divisors, whose sum is σ = 1312021401350. Its totient is φ = 1312021401348.

The previous prime is 1312021401307. The next prime is 1312021401371. The reversal of 1312021401349 is 9431041202131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 756564217249 + 555457184100 = 869807^2 + 745290^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312021401349 - 2¹¹ = 1312021399301 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1312021401349.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312021404349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656010700674 + 656010700675.

It is an arithmetic number, because the mean of its divisors is an integer number (656010700675).

Almost surely, 2^{1312021401349} is an apocalyptic number.

It is an amenable number.

1312021401349 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312021401349 is an equidigital number, since it uses as much as digits as its factorization.

1312021401349 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 31.

The spelling of 1312021401349 in words is "one trillion, three hundred twelve billion, twenty-one million, four hundred one thousand, three hundred forty-nine".