Base | Representation |
---|---|
bin | 10011000101111010101… |
… | …010100011011101110011 |
3 | 11122102120010202011221112 |
4 | 103011322222203131303 |
5 | 132444010342012242 |
6 | 2442422434143535 |
7 | 163535103333311 |
oct | 23057252433563 |
9 | 4572503664845 |
10 | 1312023000947 |
11 | 46647586380a |
12 | 192341a21bab |
13 | 96952c53299 |
14 | 477062730b1 |
15 | 241de6dac82 |
hex | 1317aaa3773 |
1312023000947 has 2 divisors, whose sum is σ = 1312023000948. Its totient is φ = 1312023000946.
The previous prime is 1312023000931. The next prime is 1312023000961. The reversal of 1312023000947 is 7490003202131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312023000947 - 24 = 1312023000931 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312023000047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656011500473 + 656011500474.
It is an arithmetic number, because the mean of its divisors is an integer number (656011500474).
Almost surely, 21312023000947 is an apocalyptic number.
1312023000947 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312023000947 is an equidigital number, since it uses as much as digits as its factorization.
1312023000947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 32.
The spelling of 1312023000947 in words is "one trillion, three hundred twelve billion, twenty-three million, nine hundred forty-seven", and thus it is an aban number.
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