1312023000931 has 2 divisors, whose sum is σ = 1312023000932. Its totient is φ = 1312023000930.

The previous prime is 1312023000913. The next prime is 1312023000947. The reversal of 1312023000931 is 1390003202131.

Together with previous prime (1312023000913) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1312023000931 - 2¹¹ = 1312022998883 is a prime.

It is a super-2 number, since 2×1312023000931² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1312023000896 and 1312023000905.

It is not a weakly prime, because it can be changed into another prime (1312023000961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656011500465 + 656011500466.

It is an arithmetic number, because the mean of its divisors is an integer number (656011500466).

Almost surely, 2^{1312023000931} is an apocalyptic number.

1312023000931 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312023000931 is an equidigital number, since it uses as much as digits as its factorization.

1312023000931 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

The spelling of 1312023000931 in words is "one trillion, three hundred twelve billion, twenty-three million, nine hundred thirty-one", and thus it is an aban number.