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1312023032017 is a prime number
BaseRepresentation
bin10011000101111010101…
…010101011000011010001
311122102120010210202120021
4103011322222223003101
5132444010344011032
62442422434543441
7163535103523015
oct23057252530321
94572503722507
101312023032017
11466475885095
12192341a37b81
1396952c64479
1447706280545
15241de6e5097
hex1317aaab0d1

1312023032017 has 2 divisors, whose sum is σ = 1312023032018. Its totient is φ = 1312023032016.

The previous prime is 1312023031981. The next prime is 1312023032057. The reversal of 1312023032017 is 7102303202131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1104010416961 + 208012615056 = 1050719^2 + 456084^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312023032017 - 27 = 1312023031889 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312023031982 and 1312023032000.

It is not a weakly prime, because it can be changed into another prime (1312023032057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656011516008 + 656011516009.

It is an arithmetic number, because the mean of its divisors is an integer number (656011516009).

Almost surely, 21312023032017 is an apocalyptic number.

It is an amenable number.

1312023032017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312023032017 is an equidigital number, since it uses as much as digits as its factorization.

1312023032017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 1312023032017 its reverse (7102303202131), we get a palindrome (8414326234148).

The spelling of 1312023032017 in words is "one trillion, three hundred twelve billion, twenty-three million, thirty-two thousand, seventeen".