Base | Representation |
---|---|
bin | 11101110101010000010110… |
… | …001011100111101100010010 |
3 | 122012112212221222001000000221 |
4 | 131311100112023213230102 |
5 | 114144112302433244442 |
6 | 1143013501420303254 |
7 | 36431051320311661 |
oct | 3565202613475422 |
9 | 565485858030027 |
10 | 131203033103122 |
11 | 38894991804612 |
12 | 1287003a3a1b2a |
13 | 5829515374966 |
14 | 2458391468dd8 |
15 | 1027d5a6b6467 |
hex | 7754162e7b12 |
131203033103122 has 32 divisors (see below), whose sum is σ = 205941034524672. Its totient is φ = 62623038613824.
The previous prime is 131203033103089. The next prime is 131203033103123. The reversal of 131203033103122 is 221301330302131.
It is a super-4 number, since 4×1312030331031224 (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (131203033103123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 235916863 + ... + 236472349.
It is an arithmetic number, because the mean of its divisors is an integer number (6435657328896).
Almost surely, 2131203033103122 is an apocalyptic number.
131203033103122 is a deficient number, since it is larger than the sum of its proper divisors (74738001421550).
131203033103122 is a wasteful number, since it uses less digits than its factorization.
131203033103122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 615802.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 131203033103122 its reverse (221301330302131), we get a palindrome (352504363405253).
The spelling of 131203033103122 in words is "one hundred thirty-one trillion, two hundred three billion, thirty-three million, one hundred three thousand, one hundred twenty-two".
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