Base | Representation |
---|---|
bin | 111101000110001010… |
… | …0111010010101111001 |
3 | 110112122210011202221202 |
4 | 1322030110322111321 |
5 | 4122201021422334 |
6 | 140135102143545 |
7 | 12323224512413 |
oct | 1721424722571 |
9 | 415583152852 |
10 | 131203310969 |
11 | 50708937505 |
12 | 21517881bb5 |
13 | c4ac288063 |
14 | 64c921b9b3 |
15 | 362d80517e |
hex | 1e8c53a579 |
131203310969 has 2 divisors, whose sum is σ = 131203310970. Its totient is φ = 131203310968.
The previous prime is 131203310933. The next prime is 131203310971. The reversal of 131203310969 is 969013302131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111662905600 + 19540405369 = 334160^2 + 139787^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131203310969 is a prime.
It is a super-2 number, since 2×1312033109692 (a number of 23 digits) contains 22 as substring.
Together with 131203310971, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131203310569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601655484 + 65601655485.
It is an arithmetic number, because the mean of its divisors is an integer number (65601655485).
Almost surely, 2131203310969 is an apocalyptic number.
It is an amenable number.
131203310969 is a deficient number, since it is larger than the sum of its proper divisors (1).
131203310969 is an equidigital number, since it uses as much as digits as its factorization.
131203310969 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 38.
The spelling of 131203310969 in words is "one hundred thirty-one billion, two hundred three million, three hundred ten thousand, nine hundred sixty-nine".
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