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131203310969 is a prime number
BaseRepresentation
bin111101000110001010…
…0111010010101111001
3110112122210011202221202
41322030110322111321
54122201021422334
6140135102143545
712323224512413
oct1721424722571
9415583152852
10131203310969
1150708937505
1221517881bb5
13c4ac288063
1464c921b9b3
15362d80517e
hex1e8c53a579

131203310969 has 2 divisors, whose sum is σ = 131203310970. Its totient is φ = 131203310968.

The previous prime is 131203310933. The next prime is 131203310971. The reversal of 131203310969 is 969013302131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111662905600 + 19540405369 = 334160^2 + 139787^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131203310969 is a prime.

It is a super-2 number, since 2×1312033109692 (a number of 23 digits) contains 22 as substring.

Together with 131203310971, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131203310569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601655484 + 65601655485.

It is an arithmetic number, because the mean of its divisors is an integer number (65601655485).

Almost surely, 2131203310969 is an apocalyptic number.

It is an amenable number.

131203310969 is a deficient number, since it is larger than the sum of its proper divisors (1).

131203310969 is an equidigital number, since it uses as much as digits as its factorization.

131203310969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26244, while the sum is 38.

The spelling of 131203310969 in words is "one hundred thirty-one billion, two hundred three million, three hundred ten thousand, nine hundred sixty-nine".