Base | Representation |
---|---|
bin | 11000011100000100… |
… | …01000000000100000 |
3 | 1020212101020022220112 |
4 | 30032002020000200 |
5 | 203332301340000 |
6 | 10005530230452 |
7 | 643064023055 |
oct | 141602100040 |
9 | 36771208815 |
10 | 13120340000 |
11 | 56230a96a9 |
12 | 2661b85428 |
13 | 13112b75c1 |
14 | 8c673302c |
15 | 51bcc3235 |
hex | 30e088020 |
13120340000 has 120 divisors (see below), whose sum is σ = 32584981968. Its totient is φ = 5198240000.
The previous prime is 13120339997. The next prime is 13120340003. The reversal of 13120340000 is 4302131.
It is an interprime number because it is at equal distance from previous prime (13120339997) and next prime (13120340003).
It is not an unprimeable number, because it can be changed into a prime (13120340003) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 2136935 + ... + 2143065.
Almost surely, 213120340000 is an apocalyptic number.
13120340000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13120340000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16292490984).
13120340000 is an abundant number, since it is smaller than the sum of its proper divisors (19464641968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13120340000 is an equidigital number, since it uses as much as digits as its factorization.
13120340000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6268 (or 6245 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 13120340000 its reverse (4302131), we get a palindrome (13124642131).
The spelling of 13120340000 in words is "thirteen billion, one hundred twenty million, three hundred forty thousand".
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