Base | Representation |
---|---|
bin | 1011111011101101011011… |
… | …0000010100001101110011 |
3 | 1201110022010112122111122021 |
4 | 2332323112300110031303 |
5 | 3204431121334040143 |
6 | 43523235504052311 |
7 | 2522630364224644 |
oct | 276732660241563 |
9 | 51408115574567 |
10 | 13120433111923 |
11 | 41a9387496255 |
12 | 157a9b2604097 |
13 | 742336808617 |
14 | 335064ab16cb |
15 | 17b45c691ced |
hex | beed6c14373 |
13120433111923 has 2 divisors, whose sum is σ = 13120433111924. Its totient is φ = 13120433111922.
The previous prime is 13120433111881. The next prime is 13120433112013. The reversal of 13120433111923 is 32911133402131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13120433111923 - 213 = 13120433103731 is a prime.
It is not a weakly prime, because it can be changed into another prime (13120433411923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560216555961 + 6560216555962.
It is an arithmetic number, because the mean of its divisors is an integer number (6560216555962).
Almost surely, 213120433111923 is an apocalyptic number.
13120433111923 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120433111923 is an equidigital number, since it uses as much as digits as its factorization.
13120433111923 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 34.
The spelling of 13120433111923 in words is "thirteen trillion, one hundred twenty billion, four hundred thirty-three million, one hundred eleven thousand, nine hundred twenty-three".
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