13120433112031 has 4 divisors (see below), whose sum is σ = 14994780699472. Its totient is φ = 11246085524592.

The previous prime is 13120433112013. The next prime is 13120433112043. The reversal of 13120433112031 is 13021133402131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13120433112031 - 2²¹ = 13120431014879 is a prime.

It is a super-2 number, since 2×13120433112031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13120433111987 and 13120433112005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13120433142031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 937173793710 + ... + 937173793723.

It is an arithmetic number, because the mean of its divisors is an integer number (3748695174868).

Almost surely, 2^{13120433112031} is an apocalyptic number.

13120433112031 is a deficient number, since it is larger than the sum of its proper divisors (1874347587441).

13120433112031 is an equidigital number, since it uses as much as digits as its factorization.

13120433112031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1874347587440.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13120433112031 its reverse (13021133402131), we get a palindrome (26141566514162).

The spelling of 13120433112031 in words is "thirteen trillion, one hundred twenty billion, four hundred thirty-three million, one hundred twelve thousand, thirty-one".