13121020212 has 24 divisors (see below), whose sum is σ = 31117612512. Its totient is φ = 4301973600.

The previous prime is 13121020183. The next prime is 13121020229. The reversal of 13121020212 is 21202012131.

It is a super-3 number, since 3×13121020212³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13121020191 and 13121020200.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8961714 + ... + 8963177.

It is an arithmetic number, because the mean of its divisors is an integer number (1296567188).

Almost surely, 2^13121020212 is an apocalyptic number.

13121020212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13121020212 is an abundant number, since it is smaller than the sum of its proper divisors (17996592300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121020212 is a wasteful number, since it uses less digits than its factorization.

13121020212 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17924959 (or 17924957 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 13121020212 its reverse (21202012131), we get a palindrome (34323032343).

The spelling of 13121020212 in words is "thirteen billion, one hundred twenty-one million, twenty thousand, two hundred twelve".