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1312102111 is a prime number
BaseRepresentation
bin100111000110101…
…0001011011011111
310101102221200201111
41032031101123133
510141344231421
6334110522451
744341453405
oct11615213337
93342850644
101312102111
11613713811
12307506427
1317bab45a8
14c6391475
157a2d0ee1
hex4e3516df

1312102111 has 2 divisors, whose sum is σ = 1312102112. Its totient is φ = 1312102110.

The previous prime is 1312102093. The next prime is 1312102139. The reversal of 1312102111 is 1112012131.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (1112012131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1312102111 - 27 = 1312101983 is a prime.

It is a super-2 number, since 2×13121021112 = 3443223899381312642, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1312102091 and 1312102100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312106111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656051055 + 656051056.

It is an arithmetic number, because the mean of its divisors is an integer number (656051056).

Almost surely, 21312102111 is an apocalyptic number.

1312102111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312102111 is an equidigital number, since it uses as much as digits as its factorization.

1312102111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

The square root of 1312102111 is about 36222.9500593201. The cubic root of 1312102111 is about 1094.7691349016.

Adding to 1312102111 its reverse (1112012131), we get a palindrome (2424114242).

The spelling of 1312102111 in words is "one billion, three hundred twelve million, one hundred two thousand, one hundred eleven".