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13121021202102 = 23311891933533643
BaseRepresentation
bin1011111011101111100111…
…0011101100111010110110
31201110100122112020120201000
42332323321303230322312
53204433322411431402
643523414112544130
72522651065011402
oct276737163547266
951410575216630
1013121021202102
1141a965944a0a0
12157ab37552046
137423cb5c4288
143350bcc38102
1517b49410ac1c
hexbeef9ceceb6

13121021202102 has 256 divisors, whose sum is σ = 32433092582400. Its totient is φ = 3898872299520.

The previous prime is 13121021202059. The next prime is 13121021202103. The reversal of 13121021202102 is 20120212012131.

13121021202102 is a `hidden beast` number, since 1 + 31 + 210 + 212 + 0 + 210 + 2 = 666.

It is a super-2 number, since 2×131210212021022 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13121021202103) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 3601705893 + ... + 3601709535.

It is an arithmetic number, because the mean of its divisors is an integer number (126691767900).

Almost surely, 213121021202102 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13121021202102, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16216546291200).

13121021202102 is an abundant number, since it is smaller than the sum of its proper divisors (19312071380298).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121021202102 is a wasteful number, since it uses less digits than its factorization.

13121021202102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4300 (or 4294 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 13121021202102 its reverse (20120212012131), we get a palindrome (33241233214233).

It can be divided in two parts, 131210 and 21202102, that added together give a palindrome (21333312).

The spelling of 13121021202102 in words is "thirteen trillion, one hundred twenty-one billion, twenty-one million, two hundred two thousand, one hundred two".