Base | Representation |
---|---|
bin | 11101110101010111111101… |
… | …101001100000110011001000 |
3 | 122012120200001221000201210201 |
4 | 131311113331221200303020 |
5 | 114144231030112142100 |
6 | 1143021333130421544 |
7 | 36431461065125434 |
oct | 3565277551406310 |
9 | 565520057021721 |
10 | 131211211443400 |
11 | 388983a9210720 |
12 | 128717412918b4 |
13 | 582a21982a36a |
14 | 24589296b79c4 |
15 | 102818868d36a |
hex | 7755fda60cc8 |
131211211443400 has 96 divisors (see below), whose sum is σ = 337766500176480. Its totient is φ = 47001030912000.
The previous prime is 131211211443343. The next prime is 131211211443413. The reversal of 131211211443400 is 4344112112131.
It is a super-2 number, since 2×1312112114434002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 444938121 + ... + 445232920.
It is an arithmetic number, because the mean of its divisors is an integer number (3518401043505).
Almost surely, 2131211211443400 is an apocalyptic number.
131211211443400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131211211443400 is an abundant number, since it is smaller than the sum of its proper divisors (206555288733080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131211211443400 is a wasteful number, since it uses less digits than its factorization.
131211211443400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 890171135 (or 890171126 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 131211211443400 its reverse (4344112112131), we get a palindrome (135555323555531).
The spelling of 131211211443400 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred eleven million, four hundred forty-three thousand, four hundred".
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