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13121130103 is a prime number
BaseRepresentation
bin11000011100001010…
…01000111001110111
31020212102201110201121
430032011020321313
5203333002130403
610005555204411
7643103523424
oct141605107167
936772643647
1013121130103
115623599284
1226622a6707
131311503113
148c689ad4b
1551bdcc3bd
hex30e148e77

13121130103 has 2 divisors, whose sum is σ = 13121130104. Its totient is φ = 13121130102.

The previous prime is 13121130101. The next prime is 13121130109. The reversal of 13121130103 is 30103112131.

13121130103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (30103112131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13121130103 - 21 = 13121130101 is a prime.

Together with 13121130101, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121130101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560565051 + 6560565052.

It is an arithmetic number, because the mean of its divisors is an integer number (6560565052).

Almost surely, 213121130103 is an apocalyptic number.

13121130103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121130103 is an equidigital number, since it uses as much as digits as its factorization.

13121130103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13121130103 its reverse (30103112131), we get a palindrome (43224242234).

The spelling of 13121130103 in words is "thirteen billion, one hundred twenty-one million, one hundred thirty thousand, one hundred three".