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13121132309993 is a prime number
BaseRepresentation
bin1011111011110000000001…
…1011100010110111101001
31201110100221021022110002002
42332330000123202313221
53204434034332404433
643523433122220345
72522653614266201
oct276740033426751
951410837273062
1013121132309993
1141a97061380a4
12157ab687b46b5
137424186269a6
143350cd8bb401
1517b49dc569e8
hexbef006e2de9

13121132309993 has 2 divisors, whose sum is σ = 13121132309994. Its totient is φ = 13121132309992.

The previous prime is 13121132309953. The next prime is 13121132310061. The reversal of 13121132309993 is 39990323112131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12121796199769 + 999336110224 = 3481637^2 + 999668^2 .

It is a cyclic number.

It is not a de Polignac number, because 13121132309993 - 28 = 13121132309737 is a prime.

It is a super-2 number, since 2×131211323099932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13121132309953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560566154996 + 6560566154997.

It is an arithmetic number, because the mean of its divisors is an integer number (6560566154997).

Almost surely, 213121132309993 is an apocalyptic number.

It is an amenable number.

13121132309993 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121132309993 is an equidigital number, since it uses as much as digits as its factorization.

13121132309993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 236196, while the sum is 47.

The spelling of 13121132309993 in words is "thirteen trillion, one hundred twenty-one billion, one hundred thirty-two million, three hundred nine thousand, nine hundred ninety-three".