13121150410000 has 100 divisors (see below), whose sum is σ = 31791588835072. Its totient is φ = 5244499728000.

The previous prime is 13121150409979. The next prime is 13121150410057. The reversal of 13121150410000 is 1405112131.

It is a tau number, because it is divible by the number of its divisors (100).

It is a self number, because there is not a number n which added to its sum of digits gives 13121150410000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 12775609 + ... + 13764391.

Almost surely, 2^{13121150410000} is an apocalyptic number.

13121150410000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13121150410000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15895794417536).

13121150410000 is an abundant number, since it is smaller than the sum of its proper divisors (18670438425072).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121150410000 is an equidigital number, since it uses as much as digits as its factorization.

13121150410000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 990138 (or 990117 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 13121150410000 its reverse (1405112131), we get a palindrome (13122555522131).

The spelling of 13121150410000 in words is "thirteen trillion, one hundred twenty-one billion, one hundred fifty million, four hundred ten thousand".