Base | Representation |
---|---|
bin | 11101110101011000010001… |
… | …100010010110111001000010 |
3 | 122012120200221011212212020211 |
4 | 131311120101202112321002 |
5 | 114144232221022042010 |
6 | 1143021430210224334 |
7 | 36431502256223530 |
oct | 3565302142267102 |
9 | 565520834785224 |
10 | 131211545112130 |
11 | 3889855a5a09aa |
12 | 12871814b850aa |
13 | 582a2709b5c92 |
14 | 245895bb33150 |
15 | 10281a7aed08a |
hex | 775611896e42 |
131211545112130 has 16 divisors (see below), whose sum is σ = 269920892802240. Its totient is φ = 44986815466992.
The previous prime is 131211545112083. The next prime is 131211545112161. The reversal of 131211545112130 is 31211545112131.
It is a junction number, because it is equal to n+sod(n) for n = 131211545112092 and 131211545112101.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 937225322160 + ... + 937225322299.
It is an arithmetic number, because the mean of its divisors is an integer number (16870055800140).
Almost surely, 2131211545112130 is an apocalyptic number.
131211545112130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131211545112130 is an abundant number, since it is smaller than the sum of its proper divisors (138709347690110).
131211545112130 is a wasteful number, since it uses less digits than its factorization.
131211545112130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1874450644473.
The product of its (nonzero) digits is 3600, while the sum is 31.
Subtracting from 131211545112130 its reverse (31211545112131), we obtain a palindrome (99999999999999).
The spelling of 131211545112130 in words is "one hundred thirty-one trillion, two hundred eleven billion, five hundred forty-five million, one hundred twelve thousand, one hundred thirty".
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