Base | Representation |
---|---|
bin | 10011000110000000011… |
… | …110101001001111101111 |
3 | 11122102210221021210101012 |
4 | 103012000132221033233 |
5 | 132444210324322231 |
6 | 2442440240535435 |
7 | 163540366405154 |
oct | 23060036511757 |
9 | 4572727253335 |
10 | 1312120542191 |
11 | 466515925a08 |
12 | 19236a62157b |
13 | 9696a2158b4 |
14 | 477151c422b |
15 | 241e8056e2b |
hex | 131807a93ef |
1312120542191 has 2 divisors, whose sum is σ = 1312120542192. Its totient is φ = 1312120542190.
The previous prime is 1312120542181. The next prime is 1312120542281. The reversal of 1312120542191 is 1912450212131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1312120542191 - 26 = 1312120542127 is a prime.
It is a super-2 number, since 2×13121205421912 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312120542101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656060271095 + 656060271096.
It is an arithmetic number, because the mean of its divisors is an integer number (656060271096).
Almost surely, 21312120542191 is an apocalyptic number.
1312120542191 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312120542191 is an equidigital number, since it uses as much as digits as its factorization.
1312120542191 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 32.
The spelling of 1312120542191 in words is "one trillion, three hundred twelve billion, one hundred twenty million, five hundred forty-two thousand, one hundred ninety-one".
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