Base | Representation |
---|---|
bin | 1011111011110000010110… |
… | …1110010011100011110111 |
3 | 1201110101011110102011102012 |
4 | 2332330011232103203313 |
5 | 3204434230101122403 |
6 | 43523450013434435 |
7 | 2522656043151254 |
oct | 276740556234367 |
9 | 51411143364365 |
10 | 13121221114103 |
11 | 41a9751281a23 |
12 | 157ab9249ba1b |
13 | 742430b4a4bb |
14 | 3350db5d642b |
15 | 17b4a6948ed8 |
hex | bef05b938f7 |
13121221114103 has 2 divisors, whose sum is σ = 13121221114104. Its totient is φ = 13121221114102.
The previous prime is 13121221114093. The next prime is 13121221114151. The reversal of 13121221114103 is 30141112212131.
It is a weak prime.
It is an emirp because it is prime and its reverse (30141112212131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13121221114103 - 216 = 13121221048567 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13121221114163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560610557051 + 6560610557052.
It is an arithmetic number, because the mean of its divisors is an integer number (6560610557052).
Almost surely, 213121221114103 is an apocalyptic number.
13121221114103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121221114103 is an equidigital number, since it uses as much as digits as its factorization.
13121221114103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 23.
Adding to 13121221114103 its reverse (30141112212131), we get a palindrome (43262333326234).
The spelling of 13121221114103 in words is "thirteen trillion, one hundred twenty-one billion, two hundred twenty-one million, one hundred fourteen thousand, one hundred three".
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