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13121221114093 is a prime number
BaseRepresentation
bin1011111011110000010110…
…1110010011100011101101
31201110101011110102011101211
42332330011232103203231
53204434230101122333
643523450013434421
72522656043151241
oct276740556234355
951411143364354
1013121221114093
1141a9751281a14
12157ab9249ba11
13742430b4a4b1
143350db5d6421
1517b4a6948ecd
hexbef05b938ed

13121221114093 has 2 divisors, whose sum is σ = 13121221114094. Its totient is φ = 13121221114092.

The previous prime is 13121221113971. The next prime is 13121221114103. The reversal of 13121221114093 is 39041112212131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12040365625929 + 1080855488164 = 3469923^2 + 1039642^2 .

It is a cyclic number.

It is not a de Polignac number, because 13121221114093 - 213 = 13121221105901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121221124093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560610557046 + 6560610557047.

It is an arithmetic number, because the mean of its divisors is an integer number (6560610557047).

Almost surely, 213121221114093 is an apocalyptic number.

It is an amenable number.

13121221114093 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121221114093 is an equidigital number, since it uses as much as digits as its factorization.

13121221114093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 31.

The spelling of 13121221114093 in words is "thirteen trillion, one hundred twenty-one billion, two hundred twenty-one million, one hundred fourteen thousand, ninety-three".