Base | Representation |
---|---|
bin | 11101110101011000111001… |
… | …010110001011011010111011 |
3 | 122012120202122201122111020002 |
4 | 131311120321112023122323 |
5 | 114144240103012224214 |
6 | 1143022020345423215 |
7 | 36431524646234141 |
oct | 3565307126133273 |
9 | 565522581574202 |
10 | 131212213008059 |
11 | 38898872603007 |
12 | 1287198079ab0b |
13 | 582a349194781 |
14 | 24589c2711591 |
15 | 10281e657d1de |
hex | 77563958b6bb |
131212213008059 has 2 divisors, whose sum is σ = 131212213008060. Its totient is φ = 131212213008058.
The previous prime is 131212213008001. The next prime is 131212213008061. The reversal of 131212213008059 is 950800312212131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131212213008059 - 228 = 131211944572603 is a prime.
Together with 131212213008061, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131212213008259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606106504029 + 65606106504030.
It is an arithmetic number, because the mean of its divisors is an integer number (65606106504030).
Almost surely, 2131212213008059 is an apocalyptic number.
131212213008059 is a deficient number, since it is larger than the sum of its proper divisors (1).
131212213008059 is an equidigital number, since it uses as much as digits as its factorization.
131212213008059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 38.
The spelling of 131212213008059 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred thirteen million, eight thousand, fifty-nine".
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