Base | Representation |
---|---|
bin | 11101110101011001101001… |
… | …100001101001111111000001 |
3 | 122012120211202001122011010221 |
4 | 131311121221201221333001 |
5 | 114144243231424320301 |
6 | 1143022232502423041 |
7 | 36431553662632066 |
oct | 3565315141517701 |
9 | 565524661564127 |
10 | 131213021323201 |
11 | 38899147903154 |
12 | 12871b67431a81 |
13 | 582a44779935c |
14 | 2458a5bc02c6d |
15 | 10282424e8da1 |
hex | 775669869fc1 |
131213021323201 has 32 divisors (see below), whose sum is σ = 133802968755456. Its totient is φ = 128651867136000.
The previous prime is 131213021323193. The next prime is 131213021323207. The reversal of 131213021323201 is 102323120312131.
It is a cyclic number.
It is not a de Polignac number, because 131213021323201 - 23 = 131213021323193 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131213021323207) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 26993007511 + ... + 26993012371.
It is an arithmetic number, because the mean of its divisors is an integer number (4181342773608).
Almost surely, 2131213021323201 is an apocalyptic number.
It is an amenable number.
131213021323201 is a deficient number, since it is larger than the sum of its proper divisors (2589947432255).
131213021323201 is a wasteful number, since it uses less digits than its factorization.
131213021323201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8233.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 131213021323201 its reverse (102323120312131), we get a palindrome (233536141635332).
The spelling of 131213021323201 in words is "one hundred thirty-one trillion, two hundred thirteen billion, twenty-one million, three hundred twenty-three thousand, two hundred one".
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