Base | Representation |
---|---|
bin | 11101110101011001101110… |
… | …001101110100101010000000 |
3 | 122012120211221112200212021222 |
4 | 131311121232031310222000 |
5 | 114144243412100310422 |
6 | 1143022244353134212 |
7 | 36431555636516021 |
oct | 3565315615645200 |
9 | 565524845625258 |
10 | 131213100010112 |
11 | 3889918826785a |
12 | 12871b8985a368 |
13 | 582a45ab89b63 |
14 | 2458a68446c48 |
15 | 102824938d842 |
hex | 77566e374a80 |
131213100010112 has 64 divisors (see below), whose sum is σ = 273626826451200. Its totient is φ = 62556128431104.
The previous prime is 131213100010099. The next prime is 131213100010177. The reversal of 131213100010112 is 211010001312131.
It is a tau number, because it is divible by the number of its divisors (64).
It is a super-2 number, since 2×1312131000101122 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69365912 + ... + 71232407.
It is an arithmetic number, because the mean of its divisors is an integer number (4275419163300).
Almost surely, 2131213100010112 is an apocalyptic number.
It is an amenable number.
131213100010112 is an abundant number, since it is smaller than the sum of its proper divisors (142413726441088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131213100010112 is a wasteful number, since it uses less digits than its factorization.
131213100010112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140598673 (or 140598661 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 131213100010112 its reverse (211010001312131), we get a palindrome (342223101322243).
The spelling of 131213100010112 in words is "one hundred thirty-one trillion, two hundred thirteen billion, one hundred million, ten thousand, one hundred twelve".
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