Base | Representation |
---|---|
bin | 11000011100001011… |
… | …10100110101100001 |
3 | 1020212110001121120021 |
4 | 30032011310311201 |
5 | 203333023410144 |
6 | 10010003113441 |
7 | 643105203151 |
oct | 141605646541 |
9 | 36773047507 |
10 | 13121310049 |
11 | 56237014a1 |
12 | 2662372881 |
13 | 1311566cb3 |
14 | 8c6906761 |
15 | 51be15884 |
hex | 30e174d61 |
13121310049 has 2 divisors, whose sum is σ = 13121310050. Its totient is φ = 13121310048.
The previous prime is 13121310047. The next prime is 13121310053. The reversal of 13121310049 is 94001312131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8861398225 + 4259911824 = 94135^2 + 65268^2 .
It is a cyclic number.
It is not a de Polignac number, because 13121310049 - 21 = 13121310047 is a prime.
Together with 13121310047, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13121310047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560655024 + 6560655025.
It is an arithmetic number, because the mean of its divisors is an integer number (6560655025).
Almost surely, 213121310049 is an apocalyptic number.
It is an amenable number.
13121310049 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121310049 is an equidigital number, since it uses as much as digits as its factorization.
13121310049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 13121310049 in words is "thirteen billion, one hundred twenty-one million, three hundred ten thousand, forty-nine".
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