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1312133132310 = 23572111337732311
BaseRepresentation
bin10011000110000001001…
…110101011000000010110
311122102211210222102202220
4103012001032223000112
5132444222040213220
62442441410443210
7163540611413100
oct23060116530026
94572753872686
101312133132310
11466521a45070
12192372893506
139696ca03380
1447716b40570
15241e91e2540
hex131813ab016

1312133132310 has 768 divisors, whose sum is σ = 4482494650368. Its totient is φ = 241416806400.

The previous prime is 1312133132309. The next prime is 1312133132311. The reversal of 1312133132310 is 132313312131.

It is an interprime number because it is at equal distance from previous prime (1312133132309) and next prime (1312133132311).

It is a super-2 number, since 2×13121331323102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312133132311) by changing a digit.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 567776055 + ... + 567778365.

It is an arithmetic number, because the mean of its divisors is an integer number (5836581576).

Almost surely, 21312133132310 is an apocalyptic number.

1312133132310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 1312133132310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2241247325184).

1312133132310 is an abundant number, since it is smaller than the sum of its proper divisors (3170361518058).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1312133132310 is a wasteful number, since it uses less digits than its factorization.

1312133132310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2469 (or 2462 counting only the distinct ones).

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 1312133132310 its reverse (132313312131), we get a palindrome (1444446444441).

The spelling of 1312133132310 in words is "one trillion, three hundred twelve billion, one hundred thirty-three million, one hundred thirty-two thousand, three hundred ten".