Base | Representation |
---|---|
bin | 11101110101011010000001… |
… | …100010100101101100110101 |
3 | 122012120212210010202110222221 |
4 | 131311122001202211230311 |
5 | 114144300043100032411 |
6 | 1143022340454122341 |
7 | 36431566654333144 |
oct | 3565320142455465 |
9 | 565525703673887 |
10 | 131213424220981 |
11 | 38899334278223 |
12 | 1287205a3503b1 |
13 | 582a4b00b38cb |
14 | 2458a9951d75b |
15 | 1028267a81071 |
hex | 7756818a5b35 |
131213424220981 has 2 divisors, whose sum is σ = 131213424220982. Its totient is φ = 131213424220980.
The previous prime is 131213424220919. The next prime is 131213424221039. The reversal of 131213424220981 is 189022424312131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 120832198216900 + 10381226004081 = 10992370^2 + 3221991^2 .
It is a cyclic number.
It is not a de Polignac number, because 131213424220981 - 29 = 131213424220469 is a prime.
It is a super-2 number, since 2×1312134242209812 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131213424226981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606712110490 + 65606712110491.
It is an arithmetic number, because the mean of its divisors is an integer number (65606712110491).
Almost surely, 2131213424220981 is an apocalyptic number.
It is an amenable number.
131213424220981 is a deficient number, since it is larger than the sum of its proper divisors (1).
131213424220981 is an equidigital number, since it uses as much as digits as its factorization.
131213424220981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 43.
The spelling of 131213424220981 in words is "one hundred thirty-one trillion, two hundred thirteen billion, four hundred twenty-four million, two hundred twenty thousand, nine hundred eighty-one".
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